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x^2-6x+7.04=0
a = 1; b = -6; c = +7.04;
Δ = b2-4ac
Δ = -62-4·1·7.04
Δ = 7.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{7.84}}{2*1}=\frac{6-\sqrt{7.84}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{7.84}}{2*1}=\frac{6+\sqrt{7.84}}{2} $
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